3w^2-42w+72=0

Solution for 3w^2-42w+72=0 equation:

3w^2-42w+72=0

a = 3; b = -42; c = +72;
Δ = b2-4ac
Δ = -422-4·3·72
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-30}{2*3}=\frac{12}{6}
=2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+30}{2*3}=\frac{72}{6}
=12
$